Diodes 1n4007

What is wiring diagram of 5 volt dc relay in 8 pin?

The relay configuration is DS2E-S-DC5V.
It is a 8 pin relay.
It is connected to +5V, Diode 1N4007, Transistor BC 548, & Load.
I want to use it in my wireless on-off switch, for my minor project

http://www.datasheetarchive.com/datasheet-pdf/07/DSA00123156.html

http://pewa.panasonic.com/pcsd/product/sign/pdf_cat/ds.pdf

http://datasheet.octopart.com/DS2E-S-DC5V-Panasonic-datasheet-2347.pdf

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Resistor ........?

if i want to lower down my voltage for example ac 240volt to dc 12 volt and i just want to use the diode & resistor. how do i Calculate the value for the resistor and for the diode which value is the best ( 1n4001 or 1n4007 )

It would be best to use a transformer to step down the voltage from 240 to 12 V. Using resistors becomes tricky because you need to take into account the total load and current requirements of the circuit. And high power resistors are very expensive and get very hot. Either diode type will work but you'll need at least 4 to construct a full wave bridge rectifier. You also need a conditioning capacitor in parallel with the load to minimize the ripple voltage.

If you really want to do it with a resistor, heres how:
Lets say the power supply your constructing need to be able to deliver 1 Amp to the load. If each diode has a voltage drop of 1 V and you use the bridge configuration you'll need two resistors that produce a voltage drop of 240V - 14V= 226V
At 1 amp the resistors will dissipate 226 watts so at the very minimum they need to be rated at 500 W. They will probably cost several hundred dollars a pop and run hot enough to cook off of.