Diode Volt

why a Laser diode gives more light with a bottom cell batteries than with a phone charger of more volts?

I connected a laser diode to a cell phone charger and the light from the laser was less Britte than when connected to a Battery, besides the laser diode got hot. So what can I do to get the light brighter and to reduce the heat in the diode.

A phone charger isn't necessarily the same thing a power supply. It's a battery charger. They often times do more than just supply a voltage. Sometimes they adjust the current over time to match what the battery needs to charge making them very bad to use for anything else.

Also, unlike a light bulb which will get brighter as voltage increases, a diode drops a certain voltage. Putting more voltage across it won't affect that fact and can actually damage it.

If you want a brighter laser diode then the only real option you have is to get a higher mW laser.

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Capacitance Vs. Voltage and Diode Test 1

How can I convert 4.5 volts to 3.2 volts using a voltage divider?

I'm powering a laser with these specifications:

650nm laser diode, 3.2 VDC
Current consumption is 40mw at 3VDC.

I've got a 4.5 volt wall wart that I was going to power it with. A friend of mine said to create a voltage divider with two resistors. I use this site:

http://ourworld.compuserve.com/homepages/Bill_Bowden/r2.htm

putting in 4.5 v as my in voltage and 3.2 as my out voltage and 0.25 as my amps but I get really odd values for the resistors (5.2 and 12.8). That doesn't seem right and I don't see resistors for sale out there with those values. What values of resistors should I use?

Thanks

pick the closest value, probably 5.6 and 12. they need to be 1 watt resistors.

but those values won't work very well. first of all they will draw about 260ma out of the battery.

Better is to use a few rectifier diodes in series with the output. 2 diodes will reduce the 4.5 volts to about 3.1 to 3.3 volts, probably good enough for the laser. And they won't draw any additional current.

Or you could use a LM123 regulator. Download the data sheet, it has schematics on it.

edit: Lee is correct, I didn't look deep enough into your question. If it's just a semiconductor diode, like an LED is, you can't drive it directly with a voltage. You need a voltage higher than 3.2 by a volt or two and a series resistor.

Measure the output of your supply, some of the cheap ones are very poorly regulated. Check that it is DC and not AC.

40mw and 3 volts is 13 ma. you want to drop 1.5 volts at 13ma, which is 100 ohms.

.