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Diode Bridge Circuits
How can I make a pulse circuit for lights that hooks up to the mains power?
I want to make a circuit that will take the mains voltage and using a 555 timer circuit, a bridge rectifier circuit (with a transformer and diodes), and a potentiometer, make a pulse wave that will make florescent lights flash at variable rates.
the 555 timer circuit can only handle voltages of DC and from like 3 to 15V though. So, how should i construct this? Should I convert to DC then back to AC? that seems a bit much!
Fluorescent lights don't flash very well because of the lag time in starting and stopping. It's best to use incandescent lights, though you can more-or-less flash fluorescent rapid-start lights using the circuit described below.
If you must work at mains voltages, the best way is to use a relay to turn the power on and off. If you can flash the lights satisfactorily by flipping the wall switch off and on, then this will work. You need to use the 555 timer to build a square-wave generator and use the output of the square wave generator to operate the relay coil. You will need a couple of stages of power transistors to expand the fan-out of the 555 IC to enough to pull a relay coil of any substance. Don't forget to add a diode to absorb the spike from the magnetic field collapsing in the coil when the circuit turns off.
There are dozens of circuit ideas available for square wave generators. Run an internet search and/or look in some electronic project books.
Good luck.
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1N4002 diodes lot of 4 build your own bridge rectifier circuit |  |
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US $.99 | 23d 20h 43m |
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Lecture - 7 Applications of Diodes
bridge circuit and full wave rectifier circuit question?
which has the higher output voltage? which has the greater current in the diodes?
A bridge rectifier has a higher output voltage since the entire AC peak-to-peak voltage appears across the output points of the bridge. The full-wave rectifier outputs both half-cycles of the AC peak voltage which averages to a lower voltage (half that of the bridge).
Current in the diodes would be the same in either case. For the bridge, it flows through two diodes in series on one half-cycle and through the opposite two on the other half-cycle. In the full-wave circuit, it flows alternately through each of the diodes.
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