Diode Bias Voltage

when diodes are reversed biased, does anyone know how to calculate the leakage current if we are given........

when diodes are reversed biased, does anyone know how to calculate the leakage current if we are given the diode voltage of -10V and the resistor voltage of 970mv? if not, what method do you suggest we use to measure the leakage current. maybe a formula would help. thanks.

It varies from diode to diode. It is just about always part of the spec (data sheet) of the diode.

You can reverse bias the diode with a battery or supply and measure it with an ammeter. Expect currents in the nA region at room temperature, for a typical small power diode. Less for a signal diode.

By "resistor voltage of 970mv" do you mean the forward drop of the diode? Typically labeled VF. This is a bit high, typical is 0.6 to 0.7 volts.

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My Wind Turbine Science Experiment.

A certain P-N junction diode of germanium has a leakage current of 10^-8 A at 127 Deg C. cont...?

The diode is forward-biased with a constant-current source of 1 mA at room temperature. If current is assumed to remain constant calculate the junction barrier voltage at 127 Deg C.

- Not sure if i'm doing the right method.

Any help is greatly appreciated.

I think I would do this in two steps.

(1) Find the applied voltage. (Va)

I = Io * exp(qVa/nkT) assume that the "n" ideality is about 1.0

ln I = ln Io * qVa/kT
-> Solve for Va.

(2) Now generally would would use Einstein's relationship to find the junction barrier voltage (Vbi) but we don' t know the doping in the depletion regions. But I think you can try:
Vbi = Va + kT/q *ln(n/p) :where ln(n/p) is the ratio of doping conc.

We know from the problem that this is a strange diode because the current is the same between room temp (27C) and 127C. If current is constant than Va must also be the same so we can have 2 eq and 2 unknowns (one for 27C and one for 127C) so
kT/q*ln(n/p) @27C = kT/q*ln(n/p) @127C to find ln(n/p) and then Vbi.

I think this will work but you will have to try it and see if you get a reasonable answer or if there is more information for this problem.