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Bridge Rectifier Circuit Diodes
Bridge Rectifier Circuit Diodes
diode rectifier bridge explain the commutation overlap angle during the process of the current commuation?


for an uncontrolled single phase rectifier bridge having a non-zero Ls in the supply side of the rectifier circuit, explain the commutation overlap angle 'u' during the process of the current commutation...
can anyone give me a brief description of the process ?

When inductance is present in the rectifier circuit, the commutation overlap angle has little to do with the recovery time of the diode. It is simply a function of the phase angle difference between the applied voltage and current.

Since the diode does not have the ability to force itself from the conducting state to the non-conducting state, it must wait for the external circuit to reach a current zero. At that time, if the diode is reverse-biased due to the externally applied voltage, it will stop conducting. (This is where the reverse recovery time comes in, for a few microseconds.)

Diodes, SCRs, and triacs are 'zero-waiting' devices, while BJTs, GTOs, and IGBTs (among others) are 'zero-forcing' devices, in the sense that they can force current in the circuit to zero, instead of waiting for it to become zero through external means.

Back to the commutation overlap angle: If you had an entirely inductive circuit, commutation overlap would be 90 degrees, and the diode would be in forward conduction for approximately 90 degrees after the applied voltage polarity goes negative across the diode. As the L/R ratio decreases, the commutation angle decreases.

An important point to note about this commutation process is that it effectively short circuits the AC supply through the rectifier impedance, as one diode continues to conduct while another one starts conducting. This creates distinct notches on the supply voltage.



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Rectifier、Bridge Rectifier、Rectifier Diode-HYmanufacturer

how to convert low AC voltage to DC voltage?


how to convert low AC voltage to DC voltage?
for example, AC 200mV want to convert exactly to DC 200mV.
I have try using bridge rectifier and a capacitor circuit to convert it, but the 0.7V will take for the diode of bridge rectifier. Anybody can teach me how to convert the lower AC voltage to DC voltage ? such as 200mV,1V or 2V etc.
Thank you

What you want the full wave conversion or half wave conversion to dc voltage.

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